Question

Jamal's deck is in the shape of a polygon and is shown on the grid below.What is the area of Jamal's deck?

Answer 1

Answer:

Area = 140 square units

Explanations:

The deck is rectangular in shape because the opposite sides are equal

Area of a rectangle = Length x Width

The length is the distance separating the points (-8, 6) and (6, 6)

`\begin{gathered} Length\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{Length = }\sqrt[]{(6-(-8))^2+(6-6)^2_{}} \\ \text{Length = }\sqrt[]{(6+8)^2} \\ \text{Length = 14 units} \end{gathered}`

The width is the distance separating the points (-8, 6) and (-8, -4)

`\begin{gathered} \text{Width = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{Width = }\sqrt[]{(-8-(-8))^2+(-4-6)^2} \\ \text{Width = }\sqrt[]{0^2+(-10)^2} \\ \text{Width = }\sqrt[]{100} \\ \text{Width = 10 units} \end{gathered}`

Area = Length x Width

Area = 14 units x 10 units

Area = 140 square units