Question

How would you solve this equation? Please show steps

Answer 1

Simple....

you have:
`3x= √(12-12x)`

So...first you know you're trying to find x..

But, you have a square root on one side...to remove this you'd have to square both sides--->>>


`(3x)^(2) = √(12-12x) ^(2)`

Leaving you with....


`9x^(2) =12-12x`

Move the terms over and set it equal to zero.

-->>


`9x^(2)+12x-12=0`

Factor out a 3...


`3( 3x^(2) +4x-4=0)`

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

Leaving you with...


`3(3x-2)(x+2)=0`

Remember you're solving for 0....

3x-2=0

3x-2=0
+2 +2

3x=2


`(3x)/(3) = (2)/(3)`

x=
`(2)/(3)`

Then-->>

x+2=0

x+2=0
-2 -2

x=-2

Thus, your answer.