Question

Find the shortest distance from D to B in the diagram below.A. √505 mB. 17 mC. 10 mD. 3√29 m

Answer 1

The shortest distance from D to B is the line that forms two square triangles on the top of the box:

Then, our problem narrows to find the length of x which is done by using the Pythagoras Theorem:

`\begin{gathered} x^2=8^2+15^2 \\ x=\sqrt[]{64+225} \\ x=\sqrt[]{289} \\ x=17 \end{gathered}`

Therefore, the distance between D and B is 17 m