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When factored completely, what are the factors of 4x^2-16 ?

User Dembele
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2 Answers

3 votes

4x^2-16=\\ 4(x^2-4)=\\ 4(x-2)(x+2)
User Slickelito
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Use:a^2-b^2=(a-b)(a+b)\\\\4x^2-16=4(x^2-4)=4(x^2-2^2)=\boxed{4(x-2)(x+2)}
User Nikita Kraev
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