Question

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral fragment?

Answer 1

Step-by-step explanation:

Density is defined as mass per unit volume.

Mathematically,
`d = (m)/(V)`

where, d = density

m = mass

V = volume

It is given that volume is
`5.74 cm^(3)` and mass is 28.7 g. Then calculate the density as follows.

`d = (m)/(V)`

=
`(28.7 g)/(5.74 cm^(3))`

=
`5 g/cm^(3)`

Therefore, we can conclude that the density of that mineral fragment is
`5 g/cm^(3)`.