352,962 views
15 votes
15 votes
Please I need to write the numbers in standard format and using an appropriate symbol and prefix

Please I need to write the numbers in standard format and using an appropriate symbol-example-1
User Daniel Vassallo
by
2.7k points

1 Answer

18 votes
18 votes

(a) 756 microseconds,


\begin{gathered} 756\text{ microseconds}=756*10^(-6)\text{ s} \\ =0.756\text{ ms } \\ \approx0.76\text{ ms} \end{gathered}

Therefore, 756 microseconds equals 0.76 ms.

(b)47210 Newtons,


\begin{gathered} 47210\text{ Newtons}=4.721*10^4\text{ N} \\ =4.721*10^4\text{ N}*(\frac{1\text{ kN}}{10^3\text{ N}}) \\ =47.21\text{ kN} \\ \approx47\text{ kN} \end{gathered}

Therefore, 47210 newtons equals 47 KN.

(c) 2,500,000 Watts,


\begin{gathered} 2500000\text{ Watts}=2.5*10^6\text{ W} \\ =2.5*10^6\text{ W}*(\frac{1\text{ MW}}{10^6}) \\ =2.5\text{ MW} \end{gathered}

Therefore, 2,500,000 watts equals 2.5 MW.

(d) 0.0008 kilometers,


\begin{gathered} 0.0008\text{ kilometers}=8*10^(-4)\text{ km} \\ =8*10^(-4)\text{ km}*(\frac{10^3\text{ m}}{1\text{ km}}) \\ =0.80\text{ m} \end{gathered}

Therefore, 0.0008 kilometres equals 0.80 m.

(e) 0.000006 farad,


\begin{gathered} 0.000006\text{ farad}=6*10^(-6)\text{ F} \\ =6*10^(-6)\text{ F}*(\frac{1\text{ }\mu F}{10^(-6)\text{ F}}) \\ =6.0\text{ }\mu F \end{gathered}

Therefore, 0.000006 farad equals 6.0 μF.

(f) Twenty-five thousand volts,


\begin{gathered} \text{ twenty-five thousand volts}=25000\text{ V} \\ =2.5*10^4\text{ V} \\ =2.5*10^4\text{ V}*(\frac{1\text{ kV}}{10^3\text{ V}}) \\ =25\text{ kV} \end{gathered}

Therefore, twenty-five thousand volts equals 25 kV.

(g) One hundred thousand ohms,


\begin{gathered} \text{ one hundred thousand ohms}=100000\text{ }\Omega \\ =1*10^5\text{ }\Omega \\ =1*10^5\text{ }\Omega*(\frac{1\text{ M}\Omega}{10^6\text{ }\Omega}) \\ =0.10\text{ M}\Omega \end{gathered}

Therefore, one hundred thousand ohms equals 0.10 MΩ.

User Zoti
by
2.3k points