170k views
1 vote
Evaluate
\int \limits^5_2 { x^(2) +3x} \, dx

User Mauridb
by
8.3k points

1 Answer

4 votes

\int \limits_2^5x^2+3x\, dx=\\ \Big[(x^3)/(3)+(3x^2)/(2)\Big]_2^5=\\ (5^3)/(3)+(3\cdot5^2)/(2)-((2^3)/(3)+(3\cdot2^2)/(2))=\\ (125)/(3)+(75)/(2)-((8)/(3)+6)=\\ (250)/(6)+(225)/(6)-((16)/(6)+(36)/(6))=\\ (475)/(6)-(52)/(6)=\\ (423)/(6)=(141)/(2)=70.5
User Lfergon
by
7.9k points