Question

How many moles of N2O3 contain 2.55x10^24 oxygen atoms?

Answer 1

moles of O = atom / avogadro's number = 2.55*10^24 / 6.022*10^23 = 4.23 mol

since each N2O3 contains 3 O atoms:
moles of N2O3 = moles of O / 3 = 1.41 mol

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Answer 2

Answer : The number of moles of
`N_2O_3` is 1.41 moles.

Explanation :

In
`N_2O_3`, there are 2 nitrogen atoms and 3 oxygen atoms.

As we know that, 1 mole of substance contains
`6.022* 10^(23)` number of atoms.

As,
`3* 6.022* 10^(23)` number of oxygen atoms contains 1 mole of
`N_2O_3`

So,
`2.55* 10^(24)` number of oxygen atoms contains
`(2.55* 10^(24))/(3* 6.022* 10^(23))=1.41` mole of
`N_2O_3`

Therefore, the number of moles of
`N_2O_3` is 1.41 moles.