14)
3(x-7)-x=2x-21
Distribute the 3 into (x-7). This will get you:
3x-21-x=2x-21
Next, combine like terms:
2x-21=2x-21
You cannot have an x on both sides of the equation, so you have to subtracts 2x on both sides
-21=-21
The answer to 14 is C because no matter what number x is, the equations will always be equal to each other
15)
3+6z=13+6z
You cannot have z on both sides of the equation, so you have to subtract 6z from both sides-
3=13
The answer to 15 would be d because both sides of the equation will never equal each other, just like 3 does not equal 13