According to the 68-95-99.7 rule,
68% of the outcome would lie within 1 standard deviation from the mean
95% of the outcome would lie within 2 standard deviations from the mean
99.7% of the outcome would lie within 3 standard deviation from the mean
Looking at the given scenario,
mean weight = 20
standard deviation = 6
Thus,
for 68%, it would lie within 20 +/ 6. This is within 14 and 26
for 95%, it would lie within 20 +/ 2 * 6. This is within 8 and 32
for 95%, it would lie within 20 +/ 3 * 6. This is within 2 and 38
The picture of the curve is shown below
1) We would apply the formula for determining z score which is expressed as
z = (x - mean)/ standard deviation
From the information given, x = 15, mean = 20, standard deviation = 6
z = (15 - 20)/6 = - 0.83
We would find the probability value corresponding z score from the normal distribution table. It is 0.203
Converting to percentage, it becomes 0.203 x 100 = 20.3%
Thus, 20.3% of fishes on this lake would weigh less than 15 pounds