Final answer:
The charge of Pb in Pb(SO3)2 is Pb4+ because it must balance the -4 charge from the two sulfite anions.
Step-by-step explanation:
The charge of Pb in Pb(SO3)2 is determined by first recognizing the total charge of the SO32- anions. As there are two sulfite ions, and each sulfite (SO32-) ion has a charge of -2, the total negative charge from the sulfites is -4. To balance this, the lead ion must have a +4 charge. Therefore, the charge of Pb in Pb(SO3)2 is Pb4+.
To determine the charge of Pb, we need to look at the compound Pb(SO3)2. The sulfate ion (SO3)2- has a charge of -2, so in order to balance the charges, the lead ion (Pb) must have a charge of +2.
Therefore, the charge of Pb in Pb(SO3)2 is +2.