Question

Find the equation of the line that passes through he points (2,6) and (-2,4)

Answer 1

First Find slope by using
`(y2-y1)/(x2-x1)`


`(4-6)/(-2-2) = (-2)/(-4) = (1)/(2)`

Now use point Slope form to find the equation of the line (y-y₁)=m(x-x₁)
(y-6)=
`(1)/(2)`(x-2)
y-6=
`(1)/(2) x-1`
y=
`(1)/(2) x+5` is your equation