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solve the followings system algrebraically (substition method method)a. -3x+7y=28 and -4x+3y=12b. x+3y= -7 and -7x-4y= -19 c. 3x+2y=4 and 6x-3y= -27d. -3x-20=-11 e. -x+4y= -5 and x-6y=7

User Akshay Shrivastav
by
2.6k points

1 Answer

25 votes
25 votes

a) -3x + 7y = 28 -4x + 3y = 12

7y - 28 = 3x

x = (7y - 28)/3

Substitution

-4(7y - 28)/3 + 3y = 12

-4(7y - 28)/3 = 12 - 3y

-4(7y - 28) = 3(12 - 3y)

-28y + 112 = 36 - 9y

112 - 36 = 28y - 9y

76 = 19y

y = 76/19

y = 4

x = [(7*4) - 28)]/3

x = [28 - 28]/3

x = 0/3

x = 0 Result x = 0, y = 4

b) x + 3y = -7 -7x - 4y = -19

x = -7 - 3y

Substitution

-7(-7 - 3y) - 4y = -19

49 + 21y - 4y = -19

17y = -19 - 49

17y = -68

y = -68/17

y = -4

x = -7 - 3(-4)

x = -7 + 12

x = 4 Result x = 4, y = -4

c) 3x + 2y = 4 6x - 3y = -27

x = (4 - 2y)/3

Substitution

6(4 - 2y)/3 - 3y = -27

6(4 - 2y)/3 = -27 + 3y

6(4 - 2y) = 3(-27 + 3y)

24 - 12y = -81 + 9y

-12y - 9y = -81 - 24

-21y = -105

y = -105/-21

y = 5

x = (4 - 2(5))/3

x = (4 - 10)/3

x = -6/3

x = -2 Result x = -2, y = 5

d) It is not complete

e) -x + 4y = -5 x - 6y = 7

x = 7 + 6y

-(7 + 6y) + 4y = -5

-7 - 6y + 4y = -5

-6y + 4y = -5 + 7

-2y = 2

y = 2/-2

y = -1

x = 7 + 6(-1)

x = 7 - 6

x = 1 Result x = 1, y = -1

User BLAZORLOVER
by
2.4k points
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