Question

What are the solutions of x2 - 2x + 17 = ?O A. X = 4i or x = -4iO B. x = 1+2i or x = 1- 2iO C. X = 1+4i or x = 1 - 4iO D. X = 2i or x = -2i

Answer 1

Given:

`x^2-2x+17=0`
`a=1\text{ ; b=-2 ; c=17}`
`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`
`\begin{gathered} x=\frac{-(-2)\pm\sqrt[]{4-4(1)(17)}}{2(1)} \\ x=\frac{2\pm\sqrt[]{4-68}}{2} \\ x=\frac{2\pm\sqrt[]{-64}}{2} \\ x=(2\pm8i)/(2) \\ x=(2(1\pm4i))/(2) \\ x=1\pm4i \end{gathered}`
`x=1+4i,1-4i`

Option C is the final answer.