Question

PLEASE ANSWER NOW =)

Rectangle ABCD has vertices A(–6, –2), B(–3, –2),
C(–3. –6), and D(–6, –6). The rectangle is translated so that the coordinates of the image are A’(–10, 1), B’(–7,1),
C’(–7, –3), and D’(–10, –3).

Which rule was used to translate the image?

T–4, 3(x, y)
T–4, 1(x, y)
T4, –1(x, y)
T4, –3(x, y)

Answer 1

the answer is T-4, 3(x,y)

Answer 2

A. T–4, 3(x, y)

Explanation:

We are given that the transformation changes the rectangle ABCD to the rectangle A'B'C'D'.

The changes in the co-ordinates are given by,

A = (-6,-2) = (-6,-2) + (-4,3) = (-10,1)

B = (-3,-2) = (-3,-2) + (-4,3) = (-7,-1)

C = (-3,-6) = (-3,-6) + (-4,3) = (-7,-3)

D = (-6,-6) = (-6,-6) + (-4,3) = (-10,-3)

So, we see that the rectangle ABCD is transformed by the co-ordinates (-4,3).

That is, it is translated 4 units to the left and 3 units upwards.

Thus, option A is correct.