Question

How many moles of MgSiO3 are in 203 g of the compound?

Answer 1

molar mass MgSiO3 = 100.38 g/mol

1 mole MgSiO3 ------------ 100.38 g
?? moles MgSiO3 ---------- 203 g

203 x 1 / 100.38 => 2.0223 moles

Answer 2

Answer: The number of moles of
`MgSiO_3` is 2.02 moles.

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

We are given:

Given mass of
`MgSiO_3` = 203 g

Molar mass of
`MgSiO_3` = 100.4 g/mol

Putting values in above equation, we get:

`\text{Moles of }MgSiO_3=(203g)/(100.4g/mol)=2.02mol`

Hence, the number of moles of
`MgSiO_3` is 2.02 moles.