Question

Graph the solution 10x + 6y =100

Answer 1

you have to put the equation in slope-intercept form, which is y=mx+b, so you have to subract 10x from both sides to get 6y=-10x+100, then divide all the terms by 6 to get y=-5/3x+16 2/3. Then all you do is graph 16 2/3 on the y axis and from that point do the slope, which is -5/3, so you have to go down on the y axis 5, and over to the right 3, and put a point. Then you just repeat this to get a few more points to be able to draw a line. (I hope this helps! sorry if i confused you even more, I'm not the best at explaining things, but hopefully I cleared things up a bit for you)

Answer 2

`standard\ equation\ linear :\\y=ax+b\\\\10x + 6y =100\ \ |\ subtract\ 10x\ to\ both\ sides \\\\6y=-10x+100\ \| \ divide \ each \ term \ by \ 2\\\\3y=-5x+50| \ divide \ each \ term \ by \ 3 \\\\y=-(5)/(3)x+(50)/(3)`


`x=1 \ \ \to\ y=-(5)/(3)*1+(50)/(3) =-(5)/(3) +(50)/(3)= (45)/(3)=15\\\\ x=10 \ \ \to\ y=-(5)/(3)*10+(50)/(3)=-(50)/(3) +(50)/(3)=0`