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The mathematics club will select a president, a vice president, and a treasurer for the club. if there are 15 members in the club, how many different selections of a president, a vice president, and a treasurer are possible if each club member can be selected to only one position? here are the choices i forgot to include them 42 455 2730 3375

1 Answer

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This is a problem of variations because the order is important, it can not be selected all of members, and can not repeat.
15V3 = 15!/(15-3)! = 2730
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