Question

How to find the area of different shapes

Answer 1

To answer this question we will use the following formula to compute the area of a trapezoid:

`Area=((MajorBase+minorbase)height)/(2),`

and the following formula to compute the area of a rhombus:

`Area=(MajorDiagonal*minordiagonal)/(2).`

(4) To answer this question we will use the following diagram as a reference:

Using the above diagram we get that:

`\begin{gathered} MajorBase=12m+6m=18m, \\ minorbase=12m, \\ height=8m. \end{gathered}`

Then the area of the trapezoid is:

`Area=((18m+12m)*8m)/(2)=(30m*8m)/(2)=120m^2.`

(5) From the given diagram we get:

Then:

`\begin{gathered} MajorBase=7cm, \\ minorbase=4cm, \\ height=3cm. \end{gathered}`

Then, the area of the trapezoid is:

`Area=((7cm+4cm)*3cm)/(2)=(11cm*3cm)/(2)=16.5cm^2.`

(6) Notice that the given figure is a rhombus, and its diagonals are:

`\begin{gathered} MajorDiagonal=8ft+9ft=17ft, \\ minordiagonal=6ft+6ft=12ft. \end{gathered}`

Therefore its area is:

`Area=(17ft*12ft)/(2)=102ft^2.`

Answer:

`\begin{gathered} 4)\text{ }120m^2. \\ 5)\text{ }16.5cm^2. \\ 6)\text{ }102ft^2. \end{gathered}`