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What is the value of (–7 3i) – (2 – 6i)? –9 9i –9 – 3i –5 – 3i –5 9i

User Hbristow
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2 Answers

7 votes
The answer to your question is -9 + 9i
User Rindeal
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2 votes

Answer:

Value of
(-7+3i)-(2-6i)= -9 + 9i

Explanation:

To find the value of the give expression:
(-7+3i)-(2-6i)

Property of subtraction of complex number states that the subtract
z_1-z_2 of two complex numbers
z_1 = a+ib and
z_2= c+id is defined as the complex number i.e


z_1 -z_2 = (a+ib)-(c+id) =(a-c) +i(b-d)

It is observed that while subtracting two complex numbers the real and imaginary parts of the system is obtained by subtracting the real and imaginary parts of the summands.

Now;


(-7+3i)-(2-6i) = (-7-2) +(3-(-6))i = -9 + (3+6)i = -9+9i

Therefore, the value of
(-7+3i)-(2-6i) is, -9 + 9i.




User Kinexus
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