Question

One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 940, find the numbers.

Answer 1

Let the first number be y.
Then First number = y
Second number: 8y
Third number= y+100
Sum is
y+8y+y+100=940
10y+100=940
10y=840
y=8.4
The first number is 8.4, the second number is 67.2 and the third number is 108.4