Question

The horizontal distance of a ramp is 19ft and the length of the ramp is 20ft. What is the vertical height of the ramp? (round to 2 decimal places)

Answer 1

The dimensions given are;

Horizontal = 19

Length (diagonal) = 20

Vertical = ???

The description would end up as a right angled triangle with one of the legs as 19 and the hypotenuse as 20. To calculate the vertical;

`\begin{gathered} 20^2=19^2+v^2 \\ 400=361+v^2 \\ \text{Subtract 361 from both sides} \\ 400-361=v^2 \\ 39=v^2 \\ \sqrt[]{39}=v \\ 6.2449=v \\ v\approx6.25\text{ (to 2 decimal places)} \end{gathered}`

The vertical height of the ramp is 6.25 ft