Question

How many Ne atoms are contained in 32.0 g of the element?

Answer 1

Approximately 9.55 x 10^23 Neon atoms (Ne) are contained in 32.0 g of the element, calculated using the molar mass and Avogadro's number.

Step-by-step explanation:

To determine how many Neon atoms (Ne) are in 32.0 g of the element, we will use the concept of the mole from the periodic table. The atomic weight of Ne is 20.18 amu on average, considering the natural abundance of its isotopes. To find the number of moles in 32.0 g of Ne, divide the mass by the atomic weight:

Moles of Ne = mass in grams ÷ atomic weight

Moles of Ne = 32.0 g ÷ 20.18 amu = 1.586 moles (approximately)

To find the number of atoms, multiply the number of moles by Avogadro's number (6.022 x 1023 atoms/mole):

Number of atoms = 1.586 moles × 6.022 x 1023 atoms/mole = 9.55 x 1023 atoms (approximately)

Therefore, there are approximately 9.55 x 1023 Ne atoms in 32.0 g of Neon.

Answer 2

mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

1 mole=6.022*10²³ particles (atoms or molecules)

Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.