Question

X^2+10x-7 / x^2+10x+25 how do i solve for x?

Answer 1

`(x^2+10x-7)/(x^2+10x+25) =0\\x^2+10x-7=0\\x= (-b\pm√(b^2-4ac))/(2a)`;
where a = 1, b = 10 and c = -7


`x=(-10\pm√(10^2-(4*1*(-7)))/(2*1)\\=(-10\pm√(100+28))/(2)=(-10\pm√(128))/(2)\\=(-10\pm√(64*2))/(2)=(-10\pm8√(2))/(2)=-5\pm4√(2)\\=-5+4√(2) \ or \ -5-4√(2)\\x=0.66 \ or \ x = -10.66`