Step-by-step explanation:
N₂ and H₂O are produced according to the following equation.
NH₄NO₂ (s) ---> N₂ (g) + 2 H₂O (g)
We know that 1 mol of a gas at STP (standard conditions of temperature and pressure) will ocuppy 22.4 L. We can use this relationship to find the number of moles present in 25.5 L of water vapor.
1 mol of H₂O = 22.4 L
moles of H₂O = 25.5 L * 1 mol/(22.4 L)
moles of H₂O = 1.14 mol
NH₄NO₂ (s) ---> N₂ (g) + 2 H₂O (g)
According to the coefficients of the reaction's equation when 2 moles of H₂O are produced, 1 mol of N₂ is also produced. Then the molar ratio between H₂O and N₂ is 2 to 1. We can use that ratio to find the number of moles of N₂ that are produced.
2 moles of H₂O : 1 mol of N₂
moles of N₂ = 1.14 moles of H₂O * 1 mol of N₂/(2 moles of H₂O)
moles of N₂ = 0.57 moles
And finally we can convert the moles of N₂ into liters.
volume of N₂ = 0.57 moles * 22.4 L/mol
volume of N₂ = 12.8 L
Answer: 12.8 L of nitrogen are produced.