Question

How many grams would 2.55 x 10²⁴ molecules of sodium nitrate weigh?

Answer 1

359.84 grams

Step-by-step explanation

Given:

Number of molecules of sodium nitrate = 2.55 x 10²⁴ molecules

What to find:

The grams of sodium nitrate in 2.55 x 10²⁴ molecules.

Solution:

The first step is to convert 2.55 x 10²⁴ molecules of sodium nitrate to moles.

1 mole of any substance contains 6.023 × 10²³ molecules

Therefore 2.55 x 10²⁴ molecules of sodium nitrate is

`\frac{2.55*10^(24)\text{ }molecules}{6.023*10^(23)\text{ }molecules}*1\text{ }mol=4.2337\text{ }mol`

The final step is to convert the moles to mass using the mole formula.

`Mole=\frac{Mass}{Molar\text{ }mass}`

Molar mass of sodium nitrate = 84.9947 g/mol

Plugging mole = 4.2337 mol and molar mass = 84.9947 g/mol, the mass of the nitrate will be:

Mass = mole x molar mass = 4.2337 mol x 84.9947 g/mol

Mass = 359.84 grams.

Hence, 2.55 x 10²⁴ molecules of sodium nitrate would weigh 359.84 grams