Question

What is the midpoint of a line segment with endpoints at (-4, 15) and (22,3)?

Answer 1

First, let us list out the given:

`\begin{gathered} (-4,15)=(x_1,y_1) \\ x_1=-4 \\ y_1=15 \end{gathered}`
`\begin{gathered} (22,3)=(x_2,y_2) \\ x_2=22 \\ y_2=3 \end{gathered}`

The formula for finding the midpoint of a line is:

`(x_m,y_m)=((x_1+x_2)/(2),(y_1+y_2)/(2))`

Substituting the given into the formula above, we will have:

`\begin{gathered} (x_m,y_m)=((x_1+x_2)/(2),(y_1+y_2)/(2)) \\ (x_m,y_m)=((-4+22)/(2),(15+3)/(2)) \\ (x_m,y_m)=((18)/(2),(18)/(2)) \\ (x_m,y_m)=(9,9) \end{gathered}`

Therefore the midpoint of a line segment with endpoints at (-4, 15) and (22,3) is (9,9)