Question

1.   Solve for p.

3(p + q) = p
 (1 point)
• q = –p
• q = –p
• p = –q
• p = –q
2.  Solve for b, then find the value of b when a = 3.

4a = 2b − 7
 (1 point)
• –
• 17
3.  Solve for r.

d = rt
 (1 point)
• r = dt
• r =
• r = d − t
4.   Find the width of a rectangle with a perimeter of 90 and a length of 15.
 (1 point)
• 90
• 15
• 45
• 30

Answer 1

1. 3(p + q) = p

-3/2q

2. 4a = 2b - 7

19/2

3. d = rt

r = d/t

4. Find the width of a rectangle with a perimeter of 90 and a length of 15.

30

Explanation:

Answer 2

1. 3( p + q ) = p
3 p + 3 q = p
3 p - p = - 3 q
2 p = - 3 q
p = - 3/2 q
2. 4 a = 2 b - 1
2 b = 4 a + 1
b = 2 a + 1/2
When a = 3:
b = 6 + 1/2 = 6.5
3. d = r t
r = d / t
4. P = 2 L + 2 W
90 = 2 * 15 + 2 W
90 = 30 + 2 W
2 W = 90 - 30
2 W = 60
W = 60 : 2
W = 30