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Find the measure of 46.97° 83°44/434 6 = [?]<<46/4548 47

Find the measure of 46.97° 83°44/434 6 = [?]<<46/4548 47-example-1
User Sebastian Zaklada
by
2.9k points

1 Answer

22 votes
22 votes

Notice that angles 4 and 5 are alternate interior angles, then:


\measuredangle5=\measuredangle4

On the other hand, angle 4 and the angle that measures 83 degrees are opposite angles, then:


\measuredangle4=83^(\circ)

Therefore:


\measuredangle5=83^(\circ)

Angles 5 and 6 are supplementary then


\begin{gathered} \measuredangle5+\measuredangle6=180^(\circ) \\ \measuredangle6=180^(\circ)-\measuredangle5=180^(\circ)-83^(\circ)=97^(\circ) \end{gathered}

Answer: 97 degrees.

User Yellow
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3.0k points
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