78.3k views
5 votes
Part a: if (6^2)^x = 1, the value of x is 0. the reason for it being 0 is because anything to the power of 0 equals 1. part b: if (6^0)^x = 1, then the value of x here is also ________

1 Answer

2 votes
The value of x is all real numbers because 6^0 is 1 and 1 raised to the power of any number will still be 1.
User Huczilla
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.