Question

A locker combination has three nonzero digits, and digits cannot be repeated. If the first digit is odd, what is the probability that the second digit is even?

A. 1/2
B. 4/9
C. 1/8
D. 1/9

Answer 1

the answer is actualy b

Explanation:

i tried the other answer from the other guy and it was incorrect

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Answer 2

`(1)/(2)` Option A.

Explanation:

A locker combination has three nonzero, non-repeated digits.

Total possibilities for the first place would be = 9 digits

Total possibilities for the second place would be = 8 digits [out of 9 no. 1 number is chosen]

and for the third place the possibilities of digits = 7 digits.

If the first digit is odd.

For the second place the even numbers are = 2, 4, 6, and 8

So the probability that the second digit is even =
`(4)/(8)` =
`(1)/(2)`

Option A.
`(1)/(2)` is the answer.