Question

A standard deck of 52 cards has 13 clubs, 13 diamonds, 13 hearts, and 13 spades.Suppose that Ramón is going to draw 2 cards without replacement. Here are some events and theirmeanings:Event MeaningD-The first card is a diamond.D2The second card is a diamond.DOThe first card iS notdiamond.DSThe second card is not a diamond. ISConsider this probability:P (Df and D$) = P(D$) • P(DS | DE)What does P (Df and D$) represent in this context?

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

Events

Step 02:

probability:

we must analyze the events to find the solution.

probability:

`P\text{ \lparen D}_{\text{ }1\text{ }}^Cand\text{ D}_2^{C\text{ }}\text{ \rparen= P \lparen D}_1^C)\text{ * P \lparen D}_2^C|\text{ D}_1^C)`

===> The probability that neither card is a diamond.

The answer is:

The probability that neither card is a diamond.