356,105 views
10 votes
10 votes
How do you factor this problem? I know you have to pull out the GCF first but I'm still stumped. 18x³-51x²+36x

User Vince Spicer
by
2.9k points

1 Answer

19 votes
19 votes
Factoring

We want to factor the following polynomial:

18x³ - 51x² + 36x​

First step

We find the Greatest Common Factors of its terms.

Since

3 · 6 = 18

3 · 17 = 51

3 · 12 = 36

we can rewrite the polynomial as:

18x³ - 51x² + 36x​

3 · 6x³ - 3 · 17x² + 3 · 12x​

Then, the common factors are

x and 3

We group those factors:

3 · 6x³ - 3 · 17x² + 3 · 12x​

3x (6x² - 17x + 12​)

Second step

Now, we have

3x (6x² - 17x + 12​)

and we want to factorise

6x² - 17x + 12

We want to factor by Grouping

Then, we have to split the middle term -17x, so we can factor it

Since -17x = -8x - 9x

we are going to use it:

6x² - 17x + 12

6x² - 8x - 9x + 12

Now, we group the first two terms together and then the last two terms together and factor by GCF:

6x² - 8x - 9x + 12

(6x² - 8x) + (-9x + 12)

For the first bynomial

Since

2 · 3 = 6

2 · 4 = 8

The first polynomial can be rewritten as:

6x² - 8x = 2 · 3x² - 2 · 4x

It has in common 2 and x, then:

2 · 3x² - 2 · 4x = 2x (3x - 4)

For the second bynomial

Since

-3 · 3 = -9

-3 · (-4) = 12

The second bynomial can be rewritten as:

9x + 12 = -3 · 3x + -3 · (-4)

They have in common -3, then:

-9x + 12 = -3(3x - 4)

Third step

Now,we have that

6x² - 8x - 9x + 12

= 2x (3x - 4) - 3(3x - 4)

Then

3x(6x² - 8x - 9x + 12) = 3x[2x (3x - 4) - 3(3x - 4)]

We can see that

2x (3x - 4)

and

- 3(3x - 4)

have in common (3x - 4)

Then

2x (3x - 4) - 3(3x - 4)

= (3x - 4)(2x - 3)

Then, the whole polynomial can be written as

18x³ - 51x² + 36x​

= 3x[2x (3x - 4) - 3(3x - 4)]

= 3x(3x - 4)(2x - 3)

Answer: 18x³ - 51x² + 36x​ = 3x(3x - 4)(2x - 3)

User Paul S Chapman
by
3.0k points