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The secondary coil of an ideal transformer has 477 turns, and the primary coil has 75 turns. What is the ratio of the current in the primary coil to the current in the secondary?

User EHayik
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1 Answer

16 votes
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The ratio of current is the inverse of the ratio of the voltage and number of turns.

Ip/Is = Ns/Np = 477/75

Ip/Is = 6.36

User Merlin Mason
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