Question

How many atoms are in 1.54 moles of bromine (Br) 35, 79.90

Answer 1

If its 1.54 moles of Br atoms then the answer is 9.274*1023 atoms. *=multiply btw

Answer 2

Answer:
`9.28* 10^(23)` atoms

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

General representation of an element is given as:
`_(Z)^(A)\textrm{X}`

`_(35)^(79.90)\textrm{Br}`

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

1 mole of bromine
`Br` contains=
`6.022* 10^(23)` atoms

1.54 moles of bromine
`Br` contains=
`(6.022* 10^(23))/(1)* 1.54=9.28* 10^(23)` atoms

Thus
`9.28* 10^(23)` atoms are present in 1.54 moles of bromine.