Question

Find the amplitude, phase shift, and period of the function. Give the exact values, not decimal approximations.y= -1+3cos(2x+pi/3)

Answer 1

The parts of a trigonometric function are:

`y=A\sin(Bx+C)+D`

Where:

A= Amplitude

2PI/B= Period

C= Phase

D= Shift

You have:

`y=3\cos(2x+(\pi)/(3))-1`

So

Amplitude= 3

Phase= π/3

Shift= -1

And the period:

`P=(2\pi)/(B)=(2\pi)/(2)=\pi`

The period = pi