Question

What is a and b for the 1st fbd on the left

Answer 1

A=50N left & B=200 N up

Step-by-step explanation

to figure out this we need to assume the object is in repose, it means teh sum of all the forces equals zero ,

hence

Step 1

the sum of horizontal forces

a) vertical

`\begin{gathered} B-200=0 \\ so,\text{ solve for B} \\ \text{add 200 in both sides} \\ B-200+200=0+200 \\ B=200 \\ so\text{ } \\ B=200\text{ N up} \end{gathered}`

b)horizontal

`\begin{gathered} 50-A=0 \\ \text{add A in both sides} \\ 50-A+A=A \\ 50=A \\ so,\text{ A is 50 N left} \end{gathered}`

therefore, the answer is

A=50N left & B=200 N up