Question

Find the x intercept
0= -.00013x^2+ x+ 10

Answer 1

0 = -0.00013x^2 + x + 10
0.00013x^2 - x - 10 = 0
13x^2 - 100000x - 1000000 = 0

`x= (-b\pm√(b^2-4ac))/(2a)`; where a = 13, b = -100000 and c = -1000000

`x=(-(-100000)\pm√((-100000)^2-(4*13*(-1000000))))/(2*13)\\=(100000\pm√(10000000000+52000000))/(26)=(100000\pm√(10052000000))/(26)\\=(100000\pm√(4000000*2513))/(26)=(100000\pm2000√(2513))/(26)`
x = 7702 or x = -10