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How many total atoms are in 0.720 g of p2o5

2 Answers

3 votes
The total is 7 atoms in all
User Trav
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4 votes

Answer:


4.92x10^(23)atoms,total

Step-by-step explanation:

Hello,

The following mole-mass relationship is applied to find the atoms of P and O, taking into account that the molar mass of P2O5 is 78g/mol:


M_(P_2O_5)=31*2+16*5=78g/mol\\atoms_(P)=0.720gP_2O_5*(1molP_2O_5)/(78gP_2O_5) *(2molP)/(1molP_2O_5)*(6.022x10^(23)atoms P)/(1molP) =4.82x10^(22)atoms P\\atoms_(O)=0.720gP_2O_5*(1molP_2O_5)/(78gP_2O_5) *(5molO)/(1molP_2O_5)*(6.022x10^(23)atoms O)/(1molO) =1.2x10^(23)atoms O

Now, by adding those atoms, one concludes:


1.2x10^(23)atoms O+4.82x10^(22)atomsP=4.92x10^(23)atoms,total

Best regards.

User Rafael Beirigo
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