Question

Given:• EFGH is a rhombus• The perimeter of EFGH is 32m70HWhich is closest to the length of EG?5.50 7.51516

Answer 1

Take into account that the each side of the rhombus has the same length, then, each side has the following length:

`\text{s}=(32)/(4)=8`

moreover, consider that segment EG is one diagonal of the rhombus, then, use the following formula to get the length of EG:

`EG=s\sqrt[]{2+2\cos \theta}`

where θ = 70.

Replace the values of θ and s into the expression fro EG:

`EG=8\sqrt[]{2+2\cos 70}=13.10`

by comparing with the given answer choices, you can conclude that the closest length is 15.