Question

Find the equation ( in terms of x) of the line through the points (-3,4) and (5,2)y=______

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

data:

point 01 (-3 , 4)

point 02 (5 , 2)

Step 02:

equation of the line:

slope:

`m\text{ =}(y2-y1)/(x2-x1)=(2-4)/(5-(-3))=(-2)/(5+3)=(-2)/(8)=(-1)/(4)`

Point-slope form of the line:

(y - y1) = m (x - x1)

(y - 4) = -1 / 4 (x - (-3))

(y - 4) = -1 /4 (x + 3)

`\begin{gathered} y\text{ - 4 =}(-1)/(4)x-(3)/(4) \\ \\ y\text{ = }(-1)/(4)x\text{ -}(3)/(4)+4 \\ \\ y\text{ = }(-1)/(4)x+(13)/(4) \end{gathered}`

The answer is:

`y=(-1)/(4)x+(13)/(4)`