Question

A heptagon has perimeter 99 feet. How long are the shorter sides

Answer 1

Given a heptagon with a perimeter of 99 ft. We know that 4 of the sides have the same length, and the remaining 3 are half as long. Let us say that the first 4 sides have a length of 2L, and the other 3 have a length of L. Then, the perimeter is:

`\begin{gathered} 2L+2L+2L+2L+L+L+L=99 \\ 11L=99 \\ L=(99)/(11) \\ L=9\text{ ft} \end{gathered}`

The shorter sides are 9 feet long