Question

Divide.(6x +5x2-21x+13) = (2x + 5)Your answer should give the quotient and the neQuotient:0Remainder:X

Answer 1

`6x^3+5x^2-21x+13\text{ }2x+5`

We start with 6x^3 divided by 2x

6x^3/2x = 3x^2

Multiply 3x^2 by (2x+5)

6x^3 + 15x^2

Now subtract the dividend by 6x^3 + 15x^2

`6x^3+5x^2-21x+13-(6x^3+15x^2)=-10x^2-21x+13`

Divide the answer again by 2x

-10x^2/2x = -5x

Multiply -5x by (2x+5)

the answer is -10x^2 - 25 x

Subtract it from -10x^2 -21x + 13

`-10x^2-21x+13-(-10x^2-25x)=4x+13`

Divide 4x by 2x

4x/2x = 2

Multiply 2 by 2x+5

The answer is 4x + 10

Subtract it from 4x+13

4x+13 - (4x+ 10) = 3

So the quotient is

`3x^2-5x+2`

The remainder is 3

To check your answer multiply the quotient by the divisor

Let us do it