Question

Question's in the image.D. 90 (its cut out the image)

Answer 1

(A)

The speed of the frank is the slope of the line equation:

`\begin{gathered} y=85x \\ \\ m=85 \end{gathered}`

Therefore the answer is 85 meters per minute or Option(C)

(B)

We have to find the walking speed of Jeffrey in meters per second, this speed is basically the slope of the graph:

`\begin{gathered} m=(\Delta y)/(\Delta x)\rightarrow(1)\text{ Slope} \\ \\ y=mx+b \end{gathered}`

Using equation (1), the slope or walking speed Jeffrey is determined as follows:

`\begin{gathered} m=(\Delta y)/(\Delta x)=(800-400)/(10-5)=(400)/(5)=80 \\ \\ \\ m=80 \\ \\ \\ \text{ Therefore the speed is:} \\ \\ \\ 80\text{ meters per minute.} \end{gathered}`

The answer, therefore, is 80 meters per minute or Option(B) for the speed of Jeffrey.

(C) How does the speed of Jeffrey compare with Frank's.

`S_F-S_J=85-80=5`

Jeffrey walks 5 meters per minute slower than Frank.

(D)

How many minutes does Jeffrey take to walk the distance that Frank walks in 16 minutes.

`\begin{gathered} \text{ Frank walks in 16 min:} \\ \\ (S_F*16)=(85*16)=1360m \\ \\ \\ ---------------------------- \\ \\ \text{ Therefore Jeffrey takes:} \\ \\ t=(S)/(v)=\frac{1360m}{80\text{ m/min}}=17min \end{gathered}`

The answer, therefore, is 17 minutes.