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36 votes
36 votes
I'm confused on how to set this up. the unit is on Trigonometry and Right Triangles if it helps

I'm confused on how to set this up. the unit is on Trigonometry and Right Triangles-example-1
User Dinesh Shah
by
2.5k points

1 Answer

17 votes
17 votes

We get thatb


\tan 60=\frac{16\sqrt[]{3}}{x}\rightarrow x=\frac{16\sqrt[]{3}}{\tan 60}=16
\sin 60=\frac{16\sqrt[]{3}}{y}\rightarrow y=\frac{16\sqrt[]{3}}{\sin 60}=32

User Arno
by
2.9k points
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