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A square residential lot is measured to be 100 feet on each side, with a possible

measurement error of 1% in each of the length and width. What is the absolute difference
between the largest and smallest possible measures of the area given this possible error?

2 Answers

5 votes

Final answer:

The absolute difference between the largest and smallest possible measures of the area of a square lot with a measurement error of 1% on each side is 400 square feet.

Step-by-step explanation:

The question is asking to find the absolute difference in area of a square lot given a possible measurement error of 1% on each side. The area of the square at exact measurement, with each side being 100 feet, is 100 feet * 100 feet = 10,000 square feet. Considering the 1% possible error, the smallest side could be 99 feet (1% less than 100 feet) and the largest side could be 101 feet (1% more than 100 feet). Therefore, the smallest possible area is 99 feet * 99 feet = 9801 square feet, and the largest possible area is 101 feet * 101 feet = 10,201 square feet. The absolute difference between the largest and smallest possible measures of the area is 10,201 square feet - 9801 square feet = 400 square feet.

User Eesh
by
7.6k points
6 votes
If I understood the question correctly, the answer would be 400
User Luckystars
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8.4k points