Given the forces:
300 N at 0 degrees
400 N at 90 degrees
Let's solve for part C and D.
Part c.
The magnitude of the resultant force.
To find the magnitude of the resultant force, apply the formula:
Where:
Fx = 300
Fy = 400
Hence, we have:
Therefore, the magnitude of the resultant force is 500 N.
• Part d.
The direction of the resultant force.
To find the direction of the resulatnt force, apply the fomula(trig ratio for tan):
Hence, we have:
Take the tan inverse of both sides:
Therefore, the direction of the resultant force is 53.13° from the x-axis.
ANSWER:
(c) 500 N
(d) 53.13°