8) solve for o≤x≤360 a) sin²x-sinx=0

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Dec 17, 2015 228k views

2 votes

8) solve for o≤x≤360
a) sin²x-sinx=0

Mathematics
high-school

Bharadwaj asked

by Bharadwaj

8.2k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

2 votes

$sin^2x-sinx=0\\\\sinx(sinx-1)=0\iff sinx=0\ or\ sinx-1=0\\\\sinx=0\iff x=0^o\ or\ x=180^o\ or\ x=360^o\\\\sinx-1=0\\sinx=1\iff x=90^o\\\\Answer:\boxed{x\in\{0^o;\ 90^o;\ 180^o;\ 360^o\}}$

Cuzzea answered Dec 21, 2015

by Cuzzea

8.5k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions