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40 votes
40 votes
Please help me with this problem I have been working on it but I keep getting it wrong this is my finale try please help.Solve for b. a = 9b²cA. b=±a√3cB. b=±ac√9C. b=±ac√3c D. b=±3ac−−√

Please help me with this problem I have been working on it but I keep getting it wrong-example-1
User Moystard
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1 Answer

28 votes
28 votes

To answer this question, we have to follow the next steps:

1. We have:


a=9b^2c

2. Divide both sides by 9c:


\begin{gathered} (a)/(9c)=(9b^2c)/(9c)=(9c)/(9c)b^2 \\ (a)/(9c)=b^2 \end{gathered}

3. Take the square root to both sides as follows:


\begin{gathered} (a)/(9c)=b^2 \\ b^2=(a)/(9c) \\ \sqrt[]{b^2}=\pm\sqrt[]{(a)/(9c)} \\ \\ \\ \\ \end{gathered}

User Stussa
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