Question

Light of two different wavelengths is used in a double-slit experiment. The location of the third order bright fringe for yellow-orange light (l= 576.4 nm) coincides with the location of the fourth order fringe for the other color's light. What is the wavelength, in nm, of the other light?

Answer 1

Given:

Wavelength of the third order bright fringe = 576.4 nm

Let's find the wavelength of the other light located in the fourth order fringe.

To find the wavelength, apply the formula:

`3\lambda_1=4\lambda_2`

Thus, we have:

`\begin{gathered} 3*576.4=4\lambda_2 \\ \\ \lambda_2=(3*576.4)/(4) \\ \\ \lambda_2=(1729.2)/(4) \\ \\ \lambda_2=432.3\text{ nm} \end{gathered}`

Therefore, the wavelength in nm of the other light is 432.3 nm.

ANSWER:

432.3 nm